parseInt with int argument vs type checking

Benchmark created by alarikh on

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parseInt
var f = function(i) {
  return parseInt(i);
}
f(12345)
ready
type check
var f = function(i) {
  return typeof i === "number" ? i : parseInt(i);
}
f(12345)
ready

Revisions

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  • Revision 1: published by alarikh on