Regex-vs-substring

Benchmark created by Ted Goldman on

Setup

var regex = /(GM)(C)(.{8})(.{9})(.{1})(.{3})(.{1})(.{3})(.{18})(.{1})(.{18})(.{18})(.{1})(.{138})(.{18})(.{1})(.{8})(.{1})/;
  var str='GMC1234567812345678911231123123456789012345678112345678901234567812345678901234567811234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456781234567890123456781123456781';
  var splits = [{name:'a',start:0,length:2},{name:'a',start:2,length:1},{name:'a',start:3,length:8},{name:'a',start:11,length:9},{name:'a',start:0,length:2},{name:'a',start:0,length:2},{name:'a',start:0,length:2},{name:'a',start:0,length:2},{name:'a',start:0,length:2},{name:'a',start:0,length:2},{name:'a',start:0,length:2}];
  var parsed={};
  var parts;

Test runner

Ready to run.

Testing in
TestOps/sec
Regex
parts = str.match(regex);
parsed.a=parts[0];
ready
Substring
for (a in splits){
  parsed[splits.name] = str.substring(splits[a].start, splits[a].length);
};
ready

Revisions

You can edit these tests or add more tests to this page by appending /edit to the URL.

  • Revision 1: published by Ted Goldman on